Answer:
1.332 Molar is the molarity of the glucose solution.
Explanation:
Molarity of the solution is the moles of compound in 1 Liter solutions.
[tex]Molarity=\frac{\text{Mass of compound}}{\text{Molar mas of compound}\times Volume (L)}[/tex]
Mass of glucose = 60.00 g
Molar mass of glucose = 180.2 g/mol
Volume of the solution = V = 250.0 mL = 0.250 L
(1 mL = 0.001 L)
[tex]Molarity=\frac{60.00 g}{180.2 g/mol\times 0.250 L}=1.332 mol/L[/tex]
1.332 Molar is the molarity of the glucose solution.
