Answer:
The probability that the whole shipment will be accepted is 0.5862.
Step-by-step explanation:
Let X = number of the aspirin tablets that doesn't meet the required specifications.
The probability of the random variable X is, P (X) = p = 0.03.
The sample of n = 47 tablets are tested from each batch.
The probability of any of the tablets being defective is independent of the others.
The probability mass function of X is,
[tex]P(X=x)={n\choose x}p^{x}(1-)^{n-x};\ x=0,1,2,3...[/tex]
Compute the probability that the whole shipment of 3000 tablets will be accepted as follows:
P (X ≤ 1) = P (X = 0) + P (X = 1)
[tex]={47\choose 0}0.03^{0}(1-0.03)^{47-0}+{47\choose 1}0.03^{1}(1-0.03)^{47-1}\\=0.2389+0.3473\\=0.5862[/tex]
Thus, the probability that the whole shipment will be accepted is 0.5862.
The sample of 47 tablets is significantly small when drawn from a population of 3000 tablets. So it is difficult to make conclusion about all such shipments of aspirin tablets.