Answer:
a) [tex]m_{CO_{2}} = 26,395,816.14\, tons[/tex], b) [tex]m_{SO_{2}} = 753,105.939\,tons[/tex]
Explanation:
a) Number of tons of carbon dioxide produced by the plant throughout the year:
A complete combustion means that a mole of [tex]CO_{2}[/tex] is produced by a mole of [tex]C[/tex] contained in coal. The yearly burnt carbon is:
[tex]m_{C} = 0.86 \cdot 8,376,726\, tons\\m_{C} = 7,203,984.36\, tons[/tex]
The amount of the yearly [tex]CO_{2}[/tex] emission is obtained:
[tex]m_{CO_{2}} = \frac{M_{CO_{2}}}{M_{C}}\cdot m_{C}[/tex]
[tex]m_{CO_{2}} = \frac{44.009\,\frac{kg}{kmol} }{12.011 \,\frac{kg}{kmol} } \times 7,203,984.36\,tons[/tex]
[tex]m_{CO_{2}} = 26,395,816.14\, tons[/tex]
b) Number of tons of tons of sulfur dioxide produced by the plant throughout the year:
The required information is found by applying the same approach seen on previous question. A complete combustion means that a mole of [tex]SO_{2}[/tex] is produced by a mole of [tex]S[/tex] contained in coal.
[tex]m_{S} = 0.045 \cdot 8,376,726\, tons\\m_{S} = 376,952.67\, tons[/tex]
The amount of the yearly [tex]SO_{2}[/tex] emission is obtained:
[tex]m_{SO_{2}} = \frac{M_{SO_{2}}}{M_{S}}\cdot m_{S}[/tex]
[tex]m_{SO_{2}} = \frac{64.062\,\frac{kg}{kmol} }{32.065 \,\frac{kg}{kmol} } \times 376,952.67\, tons[/tex]
[tex]m_{SO_{2}} = 753,105.939\,tons[/tex]
