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After the capacitor is fully charged, you switch the switch to position b at time t = 0 seconds. The voltmeter initially reads 4.5 V. After how much elapsed time (in seconds) would you expect the voltmeter to read 1/2 its initial value?

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hafsaabdulhai

Answer:

0.693RC where R is resistance in the circuit and C is capacitance of the capacitor

Explanation:

v=V×e^(-t/RC)

V:Initial Voltage during discharge

t: time

R: resistance in the discharge circuit

C: Capacitance of the capacitor

Consider the circuit in the attachment

For v=0.5V

0.5V=V×e^(-t/RC)

t=0.693RC

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