Answer:
[tex]v=3.05m/s[/tex]
Explanation:
We must know that the formula for centripetal acceleration is:
[tex]a_{cp}=\frac{v^2}{r}[/tex]
where v is the tangential speed at the rim and r the radius of the drum, so we can write:
[tex]v=\sqrt{a_{cp}r}[/tex]
which for our values is:
[tex]v=\sqrt{(30m/s^2)(0.31m)}=3.05m/s[/tex]
