Answer:
A. 1.19 * 10^(-13) N
B. 7.12 * 10^(15) m/s²
Explanation:
Parameters given:
Speed, v = 5.05 * 10^6 m/s
Angle, A = 64°
Magnetic field strength, B = 0.160T
Mass of proton, m = 1.673 * 10^(-27) kg
Charge of proton, q = 1.6023 * 10^(-19) C
A. Magnetic force is given as:
F = q*v*B*sinA
F = 1.6023 * 10^(-19) * 5.05 * 10^6 * 0.160 * sin64
F = 1.19 * 10^(-13) N
B. Force is generally given as:
F = m*a
Hence, we can find acceleration, a, by making it the subject of formula:
a = F/m
a = (1.19 * 10^(-13))/(1.673 * 10^-27)
a = 7.12 * 10^15 m/s²
Answer:
(a) the magnitude of the magnetic force on the proton is 1.16 x 10⁻¹³ N
(b) the proton's acceleration is 6.97 x 10¹³ m/s²
Explanation:
given information:
proton's speed, v = 5.05 ✕ 10⁶ m/s
angle, θ = 64°
magnetic field, B = 0.160 T ( +x direction)
(a) the magnitude of the magnetic force on the proton
F = q v B sin θ
where
F = magnetic force (N)
q = charge (C)
v = speed (m/s)
B = magnetic field (T)
θ = angle
F = q v B sin θ
proton charge, q = 1.602 x 10⁻¹⁹ C
thus,
F = (1.602 x 10⁻¹⁹) (5.05 ✕ 10⁶) (0.160) sin 64°
= 1.16 x 10⁻¹³ N
the proton's acceleration
F = m a
where
m = mass (kg)
a = acceleration (m/s²)
the mass of proton, m = 1.67 x 10⁻²⁷ kg
so,
F = m a
a = F/m
= (1.16 x 10⁻¹³)/(1.67 x 10⁻²⁷)
= 6.97 x 10¹³ m/s²
