Respuesta :
Answer:
The electrical force of attraction between the balloons is [tex]2.16\times 10^{-5}\ N[/tex].
Explanation:
Given that,
Charge 1, [tex]q_1=+3.5\times 10^{-8}\ C[/tex]
Charge 2, [tex]q_2=-2.9\times 10^{-8}\ C[/tex]
Distance between the charges, d = 0.65 m
We need to find the electrical force of attraction between two balloons. It is given by the formula as :
[tex]F=k\dfrac{q_1q_2}{d^2}\\\\F=9\times 10^9\times \dfrac{3.5\times 10^{-8}\times 2.9\times 10^{-8}}{(0.65)^2}\\\\F=2.16\times 10^{-5}\ N[/tex]
So, the electrical force of attraction between the balloons is [tex]2.16\times 10^{-5}\ N[/tex]. Hence, this is the required solution.
The electrical force of attraction between the balloons is 2.16*10^-5 N.
Calculation of the electric force:
Since there is separate charges of +3.5 × 10-8 C and -2.9 × 10-8 C when separated a distance of 0.65 m.
So,
F = kq1q2/d2
= 9*10^9*3.5× 10-8 C*2.9 × 10-8 C/0.65^2
= 2.16*10^-5 N.
hence, The electrical force of attraction between the balloons is 2.16*10^-5 N.
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