Answer:
Number of tuns in the secondary coil be 99000 volt.
Explanation:
Given that,
Number of turns in the primary coil, [tex]N_p=300[/tex]
Voltage of the primary coil, [tex]V_p=220\ V[/tex]
Voltage of the secondary coil, [tex]V_s=66000\ V[/tex]
Let number of tuns in the secondary coil be [tex]N_s[/tex]. It can be calculated using the turn and voltage ratio. It is given by :
[tex]\dfrac{N_p}{N_s}=\dfrac{V_p}{V_s}\\\\\dfrac{300}{N_s}=\dfrac{200}{66000}\\\\N_s=99000\ V[/tex]
So, the number of tuns in the secondary coil be 99000 volt. Hence, this is the required solution.