Answer:
Displacement is 72.917 m .
Explanation:
Given :
Mass of cyclist , m = 54 kg .
Initial speed , u = 3.5 m/s .
Frictional coefficient between skates and ice is , [tex]\mu= 0.024[/tex] .
We need to find its the displacement produced by it .
Frictional Force , [tex]F=\mu (mg)=0.024\times 54\times 3.5=4.536\ N.[/tex]
Therefore, its acceleration , [tex]a=\dfrac{F}{m}=\dfrac{4.536}{54}=0.084\ .[/tex]
We know , by equation of motion .
[tex]v^2-u^2=2\times a \times s\\\\s=\dfrac{v^2-u^2}{2\times a}=\dfrac{0-3.5^2}{2 \times (-0.084)}=72.917\ m.[/tex]
Hence , this is the required solution .
