Answer:
There is no net ionic equation
Explanation:
We identify the reactants and the products for the reaction
NaCN, HNO₃, NaNO₃, HCN
In this case, they are all soluble in water (aq)
We write the reaction, by the ionic form
Na⁺(aq) + CN⁻ (aq) + H⁺ (aq) + NO₃⁻(aq) → Na⁺(aq) + NO₃⁻(aq) + H⁺(aq) + CN⁻(aq)
All of the ions are spectators, they all react so there is no net ionic equation
Answer:
There is no net ionic equation
Explanation:
Step 1: Data given
sodium cyanide = NaCN
nitric acid = HNO3
sodium nitrate = NaNO3
hydrocyanic acid = HCN
Step 2: The unbalanced equation
NaCN(aq) + HNO3(aq) → NaNO3(aq) + HCN(aq)
The equation is already balanced.
Step 3: the net ionic equation
The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will , after canceling those spectator ions in both side, look like this:
Na+ + CN- + H+ NO3- → Na+ + NO3- + H+ + CN-
There is no net ionic equation
If you don't have a net ionic equation to balance, that means you have what is usually called a molecular equation (or a complete molecular equation)
