A 2.0 kg lab car moving to the right with an initial velocity of 3.0 m/s collides with a 1.0 kg lab car moving to the left with a velocity of 8.0 m/s in a inelastic collision. What us the final velocity?

Respuesta :

Answer:

[tex]v=-0.667\,\frac{m}{s}[/tex]

Explanation:

The physical model of a inelastic collision is modelled after the Principle of Momentum Conservation, that is:

[tex]m_{A} \cdot v_{A} + m_{B} \cdot v_{B} = (m_{A} + m_{B}) \cdot v[/tex]

The final velocity of the system is:

[tex]v = \frac{m_{A}\cdot v_{A} + m_{B}\cdot v_{B}}{m_{A}+m_{B}}[/tex]

[tex]v=\frac{(2\,kg)\cdot(3\,\frac{m}{s})+(1\,kg)\cdot(-8\,\frac{m}{s})}{2\,kg+1\,kg}[/tex]

[tex]v=-0.667\,\frac{m}{s}[/tex]

Answer:

Explanation:

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