Answer: f1 = 3. 5m, f2= 0.84m
Explanation:
A nearsighted person will use a concave lens.
Using the formula:
1/o + 1/i = -1/f1.......(1)
o = object distance = 3.50 m
i = image distance = infinity
f1 = focal length
Substituting into 1
1/3.50 + 1/infinity = 1/f1
1/3.50 + 0 = 1/f1
f = 3. 50m
The negative means image is formed on the same side of the lens
Farsightedness is corrected with convex lens
So using
1/o + 1/i = 1/f2
i = image distance = -0.60m
The near point is taken as the image distance
o= 0.350m
The distance of the to the eye is considered the object distance.
1/f2 = 1/.350 - 1/0.60
1/f2 = 2.857- 1.6667
1/f2 = 1.190
f2 = 1/1.190
f2 = 0.840 m