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The operating potential difference of a light bulb is 120 V. The power rating of the bulb is 70 W. (a) Find the current in the bulb. A (b) Find the bulb's resistance.

Respuesta :

Answer: I= 0.583A

R=205.83ohms

Explanation: Power= I*V

Where I= current and V = potential difference

I=P/V

I= 70/120

I=0.583A

To find resistance

Using ohms law

V= IR

R=V/I

R= 120/0.583

R= 205.83ohms

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