Answer:
2.94g/L
Explanation:
First, let us derive an expression for the density, using the ideal gas equation:
PV = nRT (1)
V = nRT/ P (2)
Recall:
Number of mole(n) = mass(m)/Molar Mass (M)
n = m/M
Substituting the value of n into equation 2:
V = nRT/ P
V = mRT/ MP
Now Divide both side by m
V/m = RT/ MP
Inverting the above equation, we have:
m/V = MP/RT
But Density = m/V
Density = MP/RT
From the question given, we obtained the following data:
P = 2.3atm
T = 305K
Molar Mass of O2 = 16x2 = 32g/mol
R = 0.082atm.L/K /mol
Density = (32x2.3)/(0.082x305)
Density = 2.94g/L
