Respuesta :
Explanation:
The given data is as follows.
initial speed (u) = 4.0 m/s, mass (m) = 12 kg
Distance (s) = 4.0 m, time (t) = 2.0 sec
First, we will calculate the acceleration as follows.
s = [tex]ut + \frac{1}{2}at^{2}[/tex]
4 = [tex]4.0 \times 2 + \frac{1}{2} \times a \times (2)^{2}[/tex]
a = -2 [tex]m/s^{2}[/tex]
Now, the final speed will be calculated as follows.
v = u + at
= [tex]4.0 + (-2) \times 2[/tex]
= 0
Therefore, change in momentum will be calculated as follows.
[tex]\Delta p[/tex] = m(v - u)
= [tex]12 \times (0 - 4)[/tex]
= -48 kg m/s
The negative sign indicates the change in momentum.
Thus, we can conclude that the change in momentum of the box during this time is most nearly 48 kg m/s.
