A ball of silly putty hits andsticks to a bowling ball that was initially at rest. After thecollision, the total kinetic energy of the bowling ball and sillyputty is

1. the same as the kinetic energy of thesilly putty before the collision
2. more than thekinetic energy of the silly putty before thecollision

3. less than the kinetic energy of thesilly putty before the collision
well since the momentum of the putty isgreat enough to move the bowling ball then wouldnt the totalkinetic energy of the bowling ball and puuty be more than thekinetic energy of the putty before the collision

Respuesta :

Answer:

3. less than the kinetic energy of thesilly putty before the collision.

Explanation:

This is because kinetic energy is dependent on the mass and velocity of an object. Mathematically, it is given as:

K. E. = ½*m*v²

Where m = mass

v = velocity

In the case of the silly putty, we know that the masses of the ball of silly putty and the bowling ball are conserved, hence, the kinetic energy depends solely on the velocity at which the object moves.

After the collision with the bowling ball, because of how heavy a bowling ball is, the speed of the silly putty and bowling ball will definitely be less than the speed of the silly putty before collision, i. e. u > v.

Hence, the kinetic energy after collision will be less than the kinetic energy before collision.

The kinetic energy of an inelastic collision would be lost.

  • Components that cling together throughout the similar result of a collision indicate that the impact seems to be relatively inelastic, as well as perfectly Inelastic implies a reduction of kinetic energy.
  • There would be permanent deformation of either the material throughout this sort of collision action, which also implies that energy is absorbed as well as "lost" owing to contact, warmth, loudness, and so on. Because of this energy loss, there will be less K.E following the contact.

Thus the response i.e., "option 3" is right.

Learn more about K.E here:

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