Answer:8.14 m/s
Explanation:
Given
height from which ball is thrown is [tex]h=24\ m[/tex]
horizontal distance moved by ball [tex]x=18\ m[/tex]
suppose [tex]u_x[/tex] is the speed by which ball is thrown horizontally
thus
vertical distance traveled in time t is given by
[tex]h=ut+\frac{1}{2}at^2[/tex]
[tex]24=0=\frac{1}{2}gt^2[/tex]
[tex]t=\sqrt{\frac{2\times 24}{9.8}}[/tex]
[tex]t=2.21\ s[/tex]
horizontal distance is given by
[tex]R=u_x\times t[/tex]
[tex]18=u_x\times 2.21[/tex]
[tex]u_x=8.14\ m/s[/tex]
