Answer:
Dulcina's collection has 57 pins
Eva's collection has 25 pins
Step-by-step explanation:
first we are going to represent the relation of pins by means of an equation
d = Dulcina
e = Eva
e + d = 82
and now we represent the relation of the collections of each one
d = e + 32
having the 2 equations we can replace the d by (e + 32) and place it in the other equation
e + d = 82
e + (e + 32) = 82
2e + 32 = 82
2e = 82 - 32
2e = 50
e = 25
Now we replace e with 25 in the second equation and get the value of d
d = e + 32
d = 25 + 32
d = 57
Answer: there are 58 pins in Dulcina's collection and 24 pins in Eva's collection
Step-by-step explanation:
Let x represent the number of pins in Dulcina's collection.
Let y represent the number of pins in Eva's collection.
Eva and Dulcina have 82 pins together. This means that
x + y = 82- - - - - - - - - - - - - - - 1
Dulcina has 34 more pins than Eva. This means that
x = y + 34
Substituting x = y + 34 into equation 1, it becomes
y + 34 + y = 82
2y + 34 = 82
2y = 82 - 34
2y = 48
y = 48/2
y = 24
x = y + 34 = 24 + 34
x = 58
