Answer:
Step-by-step explanation:
(a) Approximate the population standard deviation (?) with the sample standard deviation (s)
Approximate the standard normal distribution with the Student's t distribution
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(b) The degree of freedom =n-1=60-1=59
Given a=0.1, t(0.05, df=59) =1.67 (from student t table)
So the lower bound is
xbar -t*s/vn =41 -1.67*3/sqrt(60) =40.35
So the upper bound is
xbar +t*s/vn =41 +1.67*3/sqrt(60) =41.65