Answer:
(3) (r^2) (s) ( 3r^3 + 2r^2s - 4)
Step-by-step explanation:
For clarity please use " ^ " to indicate exponentiation:
9r5s + 6r4s2 − 12r2s => 9r5s + 6r^4s^2 − 12r^2s
Next, look at the numerica coefficients 9, 6 and -12. What is the largest divisor that goes into each evenly? 3.
Similarly, ask yourself what the largest possible r and s factors divide into 9r5s + 6r^4s^2 − 12r^2s evenly: r^2 and s.
Then 9r5s + 6r^4s^2 − 12r^2s = (3) ( 3r^5s + 2r^4s^2 - 4r^2s )
Factoring out r^2: (3) (r^2) (3r^3s + 2r^2s^2 - 4s )
Factoring out s: (3) (r^2) (s) ( 3r^3 + 2r^2s - 4)
