Given Information:
Voltage = V = 115 V
Power = P = 1430
Capacitance = 56.0 µF
Required Information:
Current = I = ?
Resistance = R = ?
Energy = E = ?
Answer:
I = 12.43 A
R = 9.25 Ω
E = 5.148x10⁶ Joules
Explanation:
(a) What is the current in the heater when the unit is operating?
According to Ohm's law
P = VI
I = P/V
I = 1430/115
I = 12.43 A
(b) What is the resistance of the heating coil?
As V = IR
R = V/I
R = 115/12.43
R = 9.25 Ω
(c) How much thermal energy is produced in 1.00 h?
E = Pt
1 hour = 3600 seconds
E = 1430*3600
E = 5.148x10⁶ Joules
Answer:
Current=12.43amperes
Resistance=9.26ohms
Thermal energy=3833640joules
Explanation:
Power(p)=1430w
Potential difference(v)=115v
Power(p)=current(I) x potential difference(v)
1430=I x 115
Current(I)=1430 ➗ 115
Current(I)=12.43ampere
P=I^2 x r where r stand for resistance
1430=(12.43)^2 x r
r=1430 ➗ (12.43)^2
r=1430 ➗ 154.5049
r=9.26ohms
Thermal energy(H)=I x v x t
t=1hr
t=(60 x 60)seconds
t=3600seconds
H=9.26 x 115 x 3600
H=3833640joules
