PERIOD OF THE LEG The period of the leg can be approximated by treating the leg as a physical pendulum, with a period of Equation representing the period of oscillation for a pendulum, where I is the moment of inertia, m is the mass, and h is the distance from the pivot point to the center of mass. The leg can be considered to be a right cylinder of constant density. For a man, the leg constitutes 16 \% of his total mass and 48 \% of his total height [21]. Find the period of the leg of a man who is 1.83 m in height with a mass of 67 kg. The moment of inertia of a cylinder rotating about a perpendicular axis at one end is ml2/3. ________________________ sec The pace of normal walking (3.0 mi/hr) is close to the natural frequency of the leg because the most efficient frequency to "drive" a system is the natural frequency. It takes less effort to walk at this rate.

Respuesta :

Answer:

Explanation:

We can see from the question that

        [tex]T 2\pi\sqrt{\frac{I}{mgh} }[/tex]

  and  [tex]I = \frac{ml^2}{3}[/tex]

           [tex]m = 16[/tex]% of  [tex]67kg[/tex]

 =>      [tex]m =10kg[/tex]

      from the question  [tex]l =48[/tex]% of [tex]1.83m[/tex]

 Substituting this into the equation

                 [tex]I = \frac{10.72 * (0.8784)^2}{3}[/tex]

        =>   [tex]I = 2.7571 \ kg m^2[/tex]

                      [tex]h = 0.5 * L[/tex]

                       [tex]h = 0.5 * 0.8784[/tex]

                     [tex]h = 0.4392m[/tex]

From the equation above

      [tex]T = 2 \pi \sqrt{\frac{2.7571}{10 .72 * 9.81 * 0.4392} }[/tex]

       [tex]T = 1,534\ sec[/tex]

           

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