What is the magnitude of the electric field at the point if the electric potential in the region is given by V 2.00xyz2, where V is in volts and coordinates x, y, and z are in meters?

Respuesta :

Answer:

Electric field at a point ( x , y , z) is [tex]E=-2yz^2-2xz^2-4xyz[/tex] .

Explanation:

Given :

Electric potential in the region is , [tex]V = 2xyz^2\ .[/tex]

We need to find the electric field .

We know , electric field , [tex]E=-\dfrac{dV}{dr}[/tex]  { Here r is distance }

In coordinate system ,

[tex]E=-\dfrac{dV}{\delta x }-\dfrac{dV}{\delta y }-\dfrac{dV}{\delta z }[/tex]  { [tex]\delta[/tex] is partial derivative }

Putting all values we get ,

[tex]E=-\dfrac{2xyz^2}{\delta x }-\dfrac{2xyz^2}{\delta y }-\dfrac{2xyz^2}{\delta z }\\\\E=-2yz^2-2xz^2-4xyz[/tex]

Hence , this is the required solution.