Answer:
CH2Cl2 produces the fewest particles
Explanation:
Step 1: Data given
1. sodium nitrate = NaNO3
2. CH2Cl2
3. sodium phosphate = Na3PO4
4. K2SO4
Step 2
NaNO3 → Na+ +NO3-
1. Sodium nitrate (NaNO3) dissociates into one Na^+ ion and one nitrate (NO3^-) ion. In total we have 2 particles.
2. CH2Cl2 is a covalent compound, so, it doesn't dissociate. So, one particle.
3) Na3PO4 → 3Na+ + PO4^3-
Sodium phosphate (Na3PO4) is an ionic compound. It dissociates into 3 Na^+ ions and 1 phosphate(PO4^-3) ion. In total, 4 particles.
4) K2SO4 → 2K+ + SO4^2-
Because K2SO4 is an "ionic" compound, it dissociates into 2 K^+ ions, and one sulfate(SO4^-2) ion. So, 3 particles.
CH2Cl2 produces only 1 particle so it has the fewest particles
