Answer:
Three resistors having resistances of R1 = 1.68 Ω , R2 = 2.51 Ω , and R3 = 4.76 Ω , are connected in parallel to a 28.0 V battery that has negligible internal resistance. Find:
a. the equivalent resistance of the combination.
b. the current in each resistor.
c. the total current through the battery.
d. the voltage across each resistor.
e. the power dissipated in each resistor.
f. Which resistor dissipates the most power: the one with the greatest resistance or the least resistance? Explain why this should be.
a. Equivalent restistance = 1/R1 + 1/R2 + 1/R3
Re.q= 1/1.68+ 1/2.51+ 1/4.76
0.595 + 0.398 + 0.21
Re.q= 1.203 ohms
b. V= IR
28= i 1.203
I= 28/1.203
Current (I) = 23.275ampere
c. Voltage = 1.203 x 23.275
V= 28V
e.Power= IV
P= 28 x 1.203
P= 33.684W
f. R3
because it carries the highest resistant with the highest voltage and power
Explanation:
