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Because not all airline passengers show up for their reserved seat, an airline sells 125 tickets for a flight that holds only 120 passengers. The probability that a passenger does not show up is 0.10, and the passengers behave independently. Round your answers to four decimal places (e.g. 98.7654).

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akindelemf

Answer:

Answer is 0.9738

Step-by-step explanation:

Given, n == 125

Probability that passenger will not show up, q = 0.10

Probability that passenger will show up, p = 1 - q

                                                                      = 1 - 0.10

                                                                      = 0.9

The probability that the flight departs with empty seats.

μ = np  ==>  125 x 0.9  ==>  112.5

σ = √npq ==> √125x0.9x0.1  ==> 3.354

∴ P( Z ≤ [tex]\frac{119 - 112.5}{3.354}[/tex] )

P ( Z ≤ 1.94 )

= 0.9738

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