Respuesta :
Answer:
When the pressure increases to 90.0 atm , the volume of the sample is 0.01467L
Explanation:
To answer the question, we note that
P₁ = 1.00 atm
V₁ = 1.32 L
P₂ = 90 atm.
According to Boyle's law, at constant temperature, the volume of gas is inversely proportional to its pressure
That is P₁V₁ = P₂V₂
Solving the above equation for V₂ we have
[tex]V_2 = \frac{P_1P_2}{P_2}[/tex] that is V₂ = [tex]\frac{1atm*1.32L}{90atm}[/tex] = [tex]\frac{11}{750}L[/tex] or 0.01467L
Answer:
The volume of the new sample is 14.7 mL
Explanation:
Step 1: data given
Initial pressure = 1.00 atm
Initial volume = 1.32 L
Final pressure = 90.0 atm
Step 2: Calculate the new volume
P1 * V1 = P2 * V2
⇒with P1 = the initial pressure = 1.00 atm
⇒with V1 = the initial volume = 1.32 L
⇒with P2 = the final pressure = 90.0 atm
⇒with V2 = the final volume = TO BE DETERMINED
V2 = (P1*V1)/P2
V2 = (1.00 atm *1.32L)/90.0 atm
V2 = 0.0147 L = 14.7 mL
The volume of the new sample is 14.7 mL
