Answer:
The chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.
Explanation:
The chemical potential of 2-propanol in solution relative to that of pure 2-propanol can be calculated using the following equation:
[tex] \mu (l) = \mu ^{\circ} (l) + R*T*ln(x) [/tex]
Where:
μ (l): is the chemical potential of 2-propanol in solution
μ° (l): is the chemical potential of pure 2-propanol
R: is the gas constant = 8.314 J K⁻¹ mol⁻¹
T: is the temperature = 82.3 °C = 355.3 K
x: is the mole fraction of 2-propanol = 0.41
[tex] \mu (l) = \mu ^{\circ} (l) + 8.314 \frac{J}{K*mol}*355.3 K*ln(0.41) [/tex]
[tex]\mu (l) = \mu ^{\circ} (l) - 2.63 \cdot 10^{3} J*mol^{-1}[/tex]
[tex] \mu (l) - \mu ^{\circ} (l) = - 2.63 \cdot 10^{3} J*mol^{-1} [/tex]
Therefore, the chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.
I hope it helps you!
