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The electric potential difference between the ground and a cloud in a particular thunderstorm is 2.5 × 109 V. What is the magnitude of the change in the electric potential energy of an electron that moves between the ground and the cloud?

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akindelemf

Answer:

U = - 4 x [tex]10^{-10}[/tex]

Explanation:

ΔV = potential difference = [tex]2.5 * 10^9[/tex] Volts

q = charge on electron = [tex]-1.6 * 10^{-19}[/tex] C

electric potential energy is given as

U = q ΔV = ( [tex]-1.6 * 10^{-19}[/tex]  ) ( [tex]2.5 * 10^9[/tex]  )

               = - 4 x [tex]10^{-10}[/tex]

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