Answer:
[tex]{P_{2}} =1.0682P_{1}[/tex]
Explanation:
This problem is based on the application of ideal gas equation. Ideal gas equation is very important tool in thermodynamics to solve many problems. So, here we solve this problem using ideal gas equation.
The temperature when the pressure is [tex]P_{1}[/tex] be [tex]T_{1}[/tex]
We convert temperature in SI unit,
[tex]T_{1}[/tex]= [tex]20^{0}C= 20 +273.15K=293.15K[/tex]
The temperature when pressure is [tex]P_{2}[/tex] be [tex]T_{2}[/tex]
[tex]T_{2}=40^{0}C= 40 +273.15K=313.15K[/tex]
By ideal gas equation,
[tex]\frac{P_{1} }{P_{2}} =\frac{T_{1} }{T_{2}}[/tex]
[tex]\frac{P_{1} }{P_{2}} =\frac{293.15}{313.15}[/tex]
[tex]\frac{P_{2} }{P_{1}} =\frac{313.15}{293.15}=1.0682[/tex]
so,
[tex]{P_{2}} =1.0682P_{1}[/tex]
Pressure become 1.0682 times.
