Respuesta :
Answer:
N2O4
Explanation:
To obtain the molecular formula of the compound, first, let us calculate the empirical formula for the compound. This is illustrated below:
N = 0.606g
O = 1.390g
Next, we divide the above by their molar masses
N = 0.606/14 = 0.0432
O = 1.390/16 = 0.0869
Next, we divide by the smallest
N = 0.0432/0.0432 = 1
O = 0.0869/0.0432 = 2
The empirical formula is NO2
The molecular formula is given by:
[NO2]n = 92
[14 + (16x2)]n = 92
[14 +32]n = 92
46n = 92
Divide both side by the coefficient of n i.e 46
n = 92/46
n = 2
The molecular formula = [NO2]n = [NO2]2 = N2O4
The molecular formula shows the actual number of atoms of each element present in a compound. The molecular formula is different for different compounds.
The molecular formula of the given compound in the question is [tex]N_2O_4[/tex]
An empirical formula is calculated first to find the molecular formula. First, let us calculate the empirical formula for the compound.
The data given in the question is as N is 0.606g and O is 1.390g
After solving the equation,
[tex]N = \frac{0.606}{14} = 0.0432\\\\O =\frac{1.390}{16} = 0.0869[/tex]
Divide it by the smallest outcomes
[tex]N = \frac{0.0432}{0.0432} = 1\\\\O = \frac{0.0869}{0.0432} = 2[/tex]
The empirical formula is NO2. Now we have to find the molecular formula.
[tex][NO2]n = 92[14 + (16x2)]n = 92[14 +32]n = 9246n = 92[/tex]
After solving the equation the value of 'n' is 2.
Hence, The molecular formula
[tex][NO2]n \\= [NO2]2\\ = N2O4[/tex]
For more information, refer to the link:-
https://brainly.com/question/1247523