The molar mass of a compound is 92 g/mol. Analysis of a sample of the compound indicates that it contains 0.606g of N and 1.390g of O. Find its molecular formula.​

Respuesta :

Answer:

N2O4

Explanation:

To obtain the molecular formula of the compound, first, let us calculate the empirical formula for the compound. This is illustrated below:

N = 0.606g

O = 1.390g

Next, we divide the above by their molar masses

N = 0.606/14 = 0.0432

O = 1.390/16 = 0.0869

Next, we divide by the smallest

N = 0.0432/0.0432 = 1

O = 0.0869/0.0432 = 2

The empirical formula is NO2

The molecular formula is given by:

[NO2]n = 92

[14 + (16x2)]n = 92

[14 +32]n = 92

46n = 92

Divide both side by the coefficient of n i.e 46

n = 92/46

n = 2

The molecular formula = [NO2]n = [NO2]2 = N2O4

The molecular formula shows the actual number of atoms of each element present in a compound. The molecular formula is different for different compounds.

The molecular formula of the given compound in the question is [tex]N_2O_4[/tex]

An empirical formula is calculated first to find the molecular formula. First, let us calculate the empirical formula for the compound.

The data given in the question is as N is 0.606g  and O is  1.390g

After solving the equation,

[tex]N = \frac{0.606}{14} = 0.0432\\\\O =\frac{1.390}{16} = 0.0869[/tex]

Divide it by the smallest outcomes

[tex]N = \frac{0.0432}{0.0432} = 1\\\\O = \frac{0.0869}{0.0432} = 2[/tex]

The empirical formula is NO2. Now we have to find the molecular formula.

 

[tex][NO2]n = 92[14 + (16x2)]n = 92[14 +32]n = 9246n = 92[/tex]

After solving the equation the value of 'n' is 2.

Hence, The molecular formula

[tex][NO2]n \\= [NO2]2\\ = N2O4[/tex]

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https://brainly.com/question/1247523