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Give the equation of the line through the point (4, 5) with a slope of - 9/2
in slope-intercept form

Respuesta :

devishri1977

Answer:

Step-by-step explanation:

y - y1 = m(x - x1)

y - 5 = -9/2*(x - 4)

y -5  = -9/2x + 9*4/2

y - 5 = -9x/2 +9*2

y-5=-9x/2 + 18

y= -9x/2 + 18 +5

y= -9x/2 + 23    {y =mx+c}

lavanyaande

The required line is 2y = -9x + 26

Step-by-step explanation:

Given,

The point is (x1 ,y1) = (4,5) and

Slope (m) = [tex]\frac{-9}{2}[/tex]

Formula

The equation of a line through point (x1 ,y1) and slope m will be

[tex]\frac{y-y1}{x-x1} = m[/tex]

Now, putting the values as (4,5) and [tex]\frac{-9}{2}[/tex] we get,

[tex]\frac{y-5}{x-4} = \frac{-9}{2}[/tex]

or, 2(y-5) = -9(x-4) [ by cross multiplication]

or, 2y - 10 = -9x + 36

or, 9x + 2y = 26

or, 2y = -9x + 26

Here is the equation of the line.

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