Answer:
The number of red circles to be added would be equal to 8 times the original amount of red circles
Step-by-step explanation:
Let
x ----> the number of red circles
y ----> the number of blue circles
Originally
[tex]\frac{x}{y}=\frac{1}{3}[/tex]
[tex]y=3x[/tex] ----> equation A
How many more circles would need to be added to make the ratio of red to blue 3:1
Let
n ----> the number of additional red circles
[tex]\frac{x+n}{y}=\frac{3}{1}[/tex] ----> equation B
substitute equation A in equation B
[tex]\frac{x+n}{3x}=\frac{3}{1}[/tex]
solve for n
[tex]x+n=9x\\n=9x-x\\n=8x[/tex]
therefore
The number of red circles to be added would be equal to 8 times the original amount of red circles
