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beavers and Sons makes two types of beaver costumes, an adult size and a child size. Due to
mand, Beavers and Sons needs to make at least 3 child costume and the company can only
make 13 costumes per day. You also can not make a negative number of adult costumes. The
adult size costs $60 to make and the child size costs $40 to make. The company can only spend
$600 on costume production,
What are some inequalities for this problem?

Respuesta :

calculista

Answer:

see the explanation

Step-by-step explanation:

Let

x ----> the number of adult size costume that Beavers and Sons makes per day

y ----> the number of child size costume that Beavers and Sons makes per day

we know that

Beavers and Sons needs to make at least 3 child costume and the company can only  make 13 costumes per day

so

[tex]y\geq 3[/tex] ----> inequality A

[tex]x+y\leq 13[/tex] ----> inequality B

You can not make a negative number of adult costumes.

so

[tex]x\geq 0[/tex] ----> inequality C

The company can only spend  $600 on costume production

so

[tex]60x+40y\leq 600[/tex] ----> inequality D

therefore

The inequalities for this problem are

[tex]y\geq 3[/tex] ----> inequality A

[tex]x+y\leq 13[/tex] ----> inequality B

[tex]x\geq 0[/tex] ----> inequality C

[tex]60x+40y\leq 600[/tex] ----> inequality D

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