For which positive integer values of $k$ does $kx^2+20x+k=0$ have rational solutions? Express your answers separated by commas and in increasing order.

Respuesta :

Answer:

-10,10

Step-by-step explanation:

The given quadratic equation is

[tex]k {x}^{2} + 20x + k = 0[/tex]

The discriminant of this equation is given by;

[tex]D = {b}^{2} - 4ac[/tex]

where a=k, b=20, c=k

For rational solutions, the discriminant must be zero.

[tex] {20}^{2} - 4 \times k \times k = 0[/tex]

Simplify to get:

[tex]400 - 4 {k}^{2} = 0[/tex]

This implies that:

[tex]400 = 4 {k}^{2} [/tex]

[tex]100 = {k}^{2} [/tex]

Take square root to get:

[tex]k = \pm\sqrt{100} [/tex]

[tex]k = \pm10[/tex]

[tex]k = - 10 \: or \: k = 10[/tex]