Respuesta :

Answer:

Y = 15sqrt(3)/4

Z = 15sqrt(3)/2

b = 45/4

Step-by-step explanation:

Sin(60) =Z/15

sqrt(3)/2 = Z/15

Z = 15sqrt(3)/2

Sin(30) = Y/Z

½ = Y/Z

Y = ½(15sqrt(3))/2 = 15sqrt(3)/4

Cos(30) = b/Z

sqrt(3)/2 = b/Z

b = 15sqrt(3)/2 × sqrt(3)/2

b = 45/4

sqrt is square root/radical

Answer:

y=15/4

z=15/2

b=

[tex] \frac{15 \sqrt{3} }{4} [/tex]

Step-by-step explanation:

Use the equations:

[tex]y = h[/tex]

Where y is adjacent to angle 60 and 30

[tex]y = \frac{h}{2} [/tex]

Where y is adjacent to angles 60 and 90

[tex] \frac{h \sqrt{3} }{2} = y[/tex]

Where y is adjacent to angles 30 and 90

First lets find z

Segment a+b is the hypotenuse in the whole triangle.

Z is adjacent to angles 60 and 90, therefore we use the second formula.

Since we know the value of hypotenuse which is 15, subsitute h to 15 then simplify

[tex] \frac{15}{2} = z[/tex]

Next is y

y is a 60-90 segment like z, but this time we're going to use z as hypotenuse. Since y is a 60-90 segment, use second equation

[tex] \frac{ \frac{15}{2} }{2} = y[/tex]

[tex] \frac{15}{4} = y[/tex]

Lastly is b

b is a 30-90 segment therefore we will use the 3rd equation. We'll use z as hypotenuse as well.

[tex] \frac{ \frac{15}{2} \sqrt{3} }{2} = b[/tex]

[tex] \frac{15 \sqrt{3} }{4} = b[/tex]