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lways use significant figure rules. Remember that these rules apply to all numbers that are measurements. Calculate the conductance of a conduit whose cross-sectional area is 3.0 cm2 and whose length is 14 cm if its conductivity is 0.90 ohm-1-cm-1. G = _____ ohm-1 5.2 0.19 0.58 0.24

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skyluke89

Answer:

[tex]0.19 \Omega^{-1}[/tex]

Explanation:

For a wire, the conductance of the wire is given by:

[tex]G=\frac{\sigma A}{L}[/tex]

where:

[tex]\sigma[/tex] is the conductivity of the material

A is the cross-sectional area of the wire

L is the length of the wire

For the wire in this problem, we have:

[tex]\sigma=0.90 \Omega^{-1} cm^{-1}[/tex] is the conductivity

[tex]A=3.0 cm^2[/tex] is the cross-sectional area

[tex]L=14 cm[/tex] is the length of the wire

Substituting the values into the equation, we find the conductance:

[tex]G=\frac{(0.90)(3.0)}{14}=0.19 \Omega^{-1}[/tex]

Answer:

0.19

Explanation:

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