The charge Q is 512 c.
Step-by-step explanation:
Step 1:
The equation is [tex]F=\frac{(q)(Q)}{R^{2}}[/tex], where q and Q are the charges, R is the distance between the charges, and F is the force between the charges.
From the question, we have;
F = 40 Newton, R = 16 m and q = 20 C.
We need to calculate Q.
Step 2:
By substituting the values of F, R, and q in the equation, we get
[tex]40 =\frac{(20)(Q)}{16^{2}}[/tex] [tex]=\frac{(20)(Q)}{256}[/tex].
We cross multiply to solve Q.
[tex]Q =\frac{(40)(256)}{20} = 2(256) = 512.[/tex]
So Q = 512 C.
