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A solution was prepared by adding 9.35 g of phosphoric acid to water had a volume of 8.78 mL. Calculate the molarity of this solution. Concentration of Phosphoric Acid Solution

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Abu99

Answer:

10.9M or

[tex]10.9 \: mol.{dm}^{ - 3} [/tex]

Explanation:

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Answer:

The concentration of H3PO4 = 10.9 M

Explanation:

Step 1: Data given

Mass of phosphoric acid = 9.35 grams

Molar mass of phosphoric acid = 97.99 g/mol

Volume = 8.78 mL = 0.00878 L

Step 2: Calculate moles of phosphoric acid

moles H3PO4 = mass H3PO4 / molar mass H3PO4

Moles H3PO4 = 9.35 grams / 97.99 g/mol

Moles H3PO4 =  0.0954 moles

Step 3: Calculate concentration of H3PO4

Concentration of H3PO4 = moles H3PO4 / volumes

Concentration H3PO4 = 0.0954 moles / 0.00878 L

Concentration H3PO4 = 10.9 M

The concentration of H3PO4 = 10.9 M

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