Does anyone happen to know how to solve this?

[tex]P^{'}[/tex] = (2, -2) after translation from P.
Step-by-step explanation:
Step 1:
The point P is at (-7, 1) on a graph. The point is translated on the graph according to T (x, y) = ([tex]x+9, y-3[/tex]).
The coordinates of point P are increased by 9 units along the x-axis while they are decreased by 3 units along the y-axis.
Step 2:
The x-axis coordinate of point P = -7.
The x-axis coordinate of point [tex]P^{'}[/tex] = -7 + 9 = 2.
The y-axis coordinate of point P = 1,
The y-axis coordinate of point [tex]P^{'}[/tex] = 1 - 3 = -2.
So the coordinate of point [tex]P^{'}[/tex] is (2, -2).