Jenny uses a roller to paint a wall. The roller has a radius of 1.75 inches and a height of 10 inches. In two rolls, what is the area of the wall that she will paint?

Respuesta :

Answer:

The area of the wall that she will paint in two rolls is 219.8 inches².

Step-by-step explanation:

Given:

Jenny uses a roller to paint a wall. The roller has a radius of 1.75 inches and a height of 10 inches.

Now, to find the area of the wall that she will paint in two rolls.

So, we find the lateral surface area of roller.

Radius (r) = 1.75 inches.

Height (h) = 10 inches.

So, to get the lateral surface area we put formula:

[tex]A_{L} =2\pi rh[/tex]

[tex]A_L=2\times 3.14\times 1.75\times 10[/tex]

[tex]A_L=109.9\ inches^2.[/tex]

Thus, the lateral surface area of the roller = 109.9 inches².

Now, to get the area of wall that she will paint in two rolls we multiply 2 by the lateral surface area of the roller:

[tex]109.9\times 2\\\\=219.8\ inches^2.[/tex]

Therefore, the area of the wall that she will paint in two rolls is 219.8 inches².

Answer:

Therefore,

The area of the wall that Jenny painted is 219.8 inches².

Step-by-step explanation:

Given:

Jenny uses a roller to paint a wall ,

Radius of roller = r = 1.75 inches

Height of roller = h = 10 inches

To Find:

Area of wall painted in two rolls = ?

Solution:

First we will calculate Circumference of the roller,

[tex]Circumference=2\pi r[/tex]

Substituting the values we get

[tex]Circumference=2\times 3.14\times 1.75=10.99\ inches[/tex]

One Roll of roller is the one full rotation of the roller and one full rotation length, is the circumference length.

[tex]Circumference=one\ roll[/tex]

For two roll

[tex]Two\ roll=Twice\ Circumference[/tex]

Substituting the values we get

[tex]Two\ roll=2\times 10.99 =21.98\ inches[/tex]

Now,

Height of roller = h = 10 inches

Two Roll cover distance = 21.98 inches

Painted Area will be of Rectangular shape of Dimensions 21.98 inches by 10 inches.

Let Length = 21.98 inches, Width = height = 10 inches

[tex]Area\ of\ Rectangle = Length\times Width[/tex]

Substituting the values we get

[tex]\textrm{Painted Area for two Rolls} = 21.98\times 10 =219.8\ inches^{2}[/tex]

Therefore,

The area of the wall that Jenny painted is 219.8 inches².