The ordered pairs of the equation are [tex](-2,\frac{7}{3})[/tex], [tex](-1,\frac{5}{3} )[/tex], [tex](0,1)[/tex],[tex](1,\frac{1}{3})[/tex] and [tex](2,-\frac{1}{3} )[/tex]
Explanation:
The given equation is [tex]y=-\frac{2}{3} x+1[/tex]
We need to find the five ordered pairs to the equation and also to determine its graph.
First, we shall find the ordered pairs by substituting the values for x in the equation.
For [tex]x=-2[/tex], we have,
[tex]y=-\frac{2}{3} (-2)+1[/tex]
[tex]y=\frac{4}{3}+1[/tex]
[tex]y=\frac{7}{3}[/tex]
Thus, the ordered pair is [tex](-2,\frac{7}{3})[/tex]
For [tex]x=-1[/tex],
[tex]y=-\frac{2}{3} (-1)+1[/tex]
[tex]=\frac{2}{3} +1[/tex]
[tex]=\frac{5}{3}[/tex]
Thus, the ordered pair is [tex](-1,\frac{5}{3} )[/tex]
For [tex]x=0[/tex] ,
[tex]y=-\frac{2}{3} (0)+1[/tex]
[tex]=1[/tex]
Thus, the ordered pair is [tex](0,1)[/tex]
For [tex]x=1[/tex] ,
[tex]y=-\frac{2}{3} (1)+1[/tex]
[tex]=-\frac{2}{3} +1[/tex]
[tex]=\frac{1}{3}[/tex]
Thus, the ordered pair is [tex](1,\frac{1}{3})[/tex]
For [tex]x=2[/tex] ,
[tex]y=-\frac{2}{3} (2)+1[/tex]
[tex]=-\frac{4}{3} +1[/tex]
[tex]=-\frac{1}{3}[/tex]
Thus, the ordered pair is [tex](2,-\frac{1}{3} )[/tex]
Hence, the ordered pairs are [tex](-2,\frac{7}{3})[/tex], [tex](-1,\frac{5}{3} )[/tex], [tex](0,1)[/tex],[tex](1,\frac{1}{3})[/tex] and [tex](2,-\frac{1}{3} )[/tex]
The graph of the equation can be determined by plotting these coordinates in the graph.
The image of the graph of the equation is attached below:
