current flowing through the given circuit is 3 A
Explanation:
When the resistances are connected in series , the total resistance is the sum of individual resistances .
Thus R = R₁ + R₂
here R₁ is resistance of 10 ohms
and R₂ is resistance of 4 ohms .
Thus total resistance R = 10 + 4 = 14 ohm .
The potential difference applied = 42 volt
Thus current I = [tex]\frac{Potential}{Resistance}[/tex] = [tex]\frac{42}{14}[/tex] = 3 A
Thus current through the circuit is 3 Ampere
