Respuesta :
Answer:
2.65sec
Step-by-step explanation:
h=v sin25 *t -1/2g t^2
-6=95 sin25 * t+1/2*32 t^2
t=2.65 sec
Using velocity and acceleration, the time taken for the ball to hit the ground is 2.65seconds.
What is velocity?
Velocity is a vector quantity "the rate at which an object changes its position".
What is acceleration?
Acceleration is the "rate at which velocity changes with time".
According to the question,
A ball is thrown with velocity 95 feet/sec at an angle 25° above the ground from the height of 6 feet. Acceleration due to the gravity is 32 feet/s².
In order to find the time taken by the ball to hit the ground:
To calculate rise time:
Velocity at the time zero (V₀) = velocity × sin 25°
= 95 × 0.4226
= 40.1 feet per second
velocity = velocity at time of zero + gravity × Time at zero(T₀)
= 40.1 + (-32)(T₀)
T₀ = [tex]\frac{40.1}{32}[/tex]
T₀ = 1.25 seconds
To calculate height: velocity = (V₀)² + 2 × gravity × height.
= (40.1)² + (2 × 32 × height)
Height = 25.1 feet.
maximum height = 6 + 25.1 = 31.5 feet
16 (time)² = 31.5
Time at falling (T₁) = 1.40 seconds
Time taken by the ball to reach the ground = T₀ + T₁ = 1.25 + 1.40
= 2.65 seconds.
Hence, the time taken by the ball to reach the ground is 2.65 seconds.
Learn more about velocity here
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