Explanation:
The intensity of sound is inversely proportional to the square of distance between source and the observer .
Thus Intensity at a distance 25 m is I₁ ∝ [tex]\frac{1}{r_1^2}[/tex] I
Similarly the intensity at a distance 50 m is I₂ ∝ [tex]\frac{1}{r_2^2}[/tex] II
Dividing II by I , we have
[tex]\frac{I_2}{I_1}[/tex] = [tex]\frac{r_1^2}{r_2^2}[/tex] = [tex]\frac{25^2}{50^2}[/tex] = [tex]\frac{1}{4}[/tex]
Thus I₂ = [tex]\frac{1}{4}[/tex] x 0.06 = 0.015 W m⁻²