Respuesta :
Option D: II and IV represents the average rate of change in the number of bacteria for the first 5 minutes in the experiment
Explanation:
Given that the number of bacteria in the colony t minutes after the initial count is modeled by the function [tex]f(t)=4(2)^t[/tex]
We need to determine the value and unit that represent the average rate of change in the number of bacteria for the first 5 minutes of the experiment.
The rate of change of bacteria can be determined using the slope formula.
The number of bacteria at time [tex]t=0[/tex] is given by
[tex]f(0)=4(2)^0[/tex]
[tex]f(0)=4[/tex]
The number of bacteria at time [tex]t=5[/tex] is given by
[tex]f(5)=4(2)^5[/tex]
[tex]f(5)=4(32)[/tex]
[tex]f(5)=128[/tex]
The average rate of change is given by
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
Substituting the coordinates [tex](0,4)[/tex] and [tex](5,128)[/tex] , we have,
[tex]m=\frac{128-4}{5-0}[/tex]
[tex]m=\frac{124}{5}[/tex]
[tex]m=24.8[/tex]
Thus the average rate of change is 24.8 bacteria per minute.
Therefore, Option D is the correct answer.
The average rate of change in the number of bacteria for the first 5 minutes of the experiment is 24.8 bacteria per minute.
Given function is,
[tex]f(t) = 4(2^t)[/tex]
What is the average rate of change?
It is a measure of how much the function changed per unit, on average, over an interval.
[tex]f(0) = 4(2^0) = 4\\f(5) = 4(2^5) = 128[/tex]
The average rate of change
[tex]=\frac{f(5)-f(0)}{5-0}[/tex]
[tex]=\frac{128-4}{5} \\\\=\frac{124}{5\\}[/tex]
[tex]=24.8[/tex]
Therefore, the average rate of change in the number of bacteria for the first 5 minutes of the experiment is 24.8 bacteria per minute.
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