Answer:
[tex]\frac{7(x+2)(x+6)}{(x+1)(x-3)}[/tex]
Step-by-step explanation:
The vertical asymptotes need to be in the denominator. They become VA's when that small expression value equals zero.
x=-2 will become (x+2)
and x=-6 will become (x+6)
The x intercepts will be in the numerator.
x=-1 will go with (x+1) and x=3 will go with (x-3)
The horizontal A must be the quotient of the coefficient of the numerator and denominator, since both the top and bottom have the same power.
To make the quotient 7, we place a seven in the numerator so 7/1=7.
