The acceleration of car is 0.2 ms⁻²
Explanation:
When the car moves , the distance covered is calculated by the relation
S = u t + [tex]\frac{1}{2}[/tex] a t²
In this question u = 0 , because car was at rest initially
Thus S = [tex]\frac{1}{2}[/tex] a t²
here S is displacement and a is the acceleration of car
Therefore 360 = [tex]\frac{1}{2}[/tex] a ( 60 )²
Because time taken is one minute or 60 seconds
Therefore a = [tex]\frac{360x2}{3600}[/tex]
or a = 0.2 m s⁻²
