The density of the gold is calculated to be "19,300 kg/m³".
Explanation:
Given:
Volume = 2cm³
Mass = 38.6 grams.
To Find:
Density of the gold = ?
Solution:
Density is obtained by dividing mass of the sample by its volume and it is given in the units of kg/m³.
Mass in grams is converted into kg as,
1 g = 0.001 kg
38. 6 g = [tex]\frac{38.6}{1000} = 0.0386 kg[/tex]
Now we have to convert cm³ to m³ as,
1 cm³ = 10⁻⁶ m³
2 cm³ = 2 × 10⁻⁶ m³
So Density = [tex]\frac{0.0386 k g}{2 \times 10^{-6} m^{3}}=19,300 \mathrm{kg} / \mathrm{m}^{3}[/tex]
Physical properties of Gold:
