Can someone help me please

Step-by-step explanation:
[tex] \tan \angle A = \frac{BC }{AC} \\ \\ \therefore \tan \angle A = \frac{8 }{2} \\ \\ \therefore \tan \angle A = 4 \\ \\ \therefore \angle A = { \tan}^{ - 1} 4\\ \\ \therefore \angle A = { \tan}^{ - 1} tan(75.96 \degree) \\ \\ \therefore \angle A = 75.96 \degree \\ or \: \\ \angle A = 75 \degree[/tex]
Answer:
Step-by-step explanation:
Triangle ABC is a right angle triangle.
From the given right angle triangle,
AB represents the hypotenuse of the right angle triangle.
With m∠A as the reference angle,
AC represents the adjacent side of the right angle triangle.
BC represents the opposite side of the right angle triangle.
To determine m∠A, we would apply
the Tangent trigonometric ratio.
Tan θ, = opposite side/adjacent side. Therefore,
Tan A = 8/2 = 4
∠A = Tan^-1(4)
∠A = 79.96° to the nearest hundredth.